A rectangular weir 0.75 m high and 1.5 m long is to be used for discharging water from a tank under a head of 0.5 m. Estimate the discharge (i) when it is used as a suppressed weir (ii) when it is used as a contract weir. Use Rehbock equation for estimating Cd in both cases.
Data:
Weir height (P) = 0.75 m
Width of weir (B) = 1.5 m
Head (H) = 0.5 m
Formulae:
Rehbock equation
\(\displaystyle C_d = 0.605 + \frac{1}{1000H} + \frac{0.08H}{P} \)
H and P in meter
Suppressed weir
\(\displaystyle Q = C_d \frac{2}{3}B\sqrt{2g}\;H^{3/2} \)
Contracted weir
\(\displaystyle Q = C_d \frac{2}{3}(B-0.1nH)\sqrt{2g}\;H^{3/2} \)
Where n = number of contractions
Q = flow rate
Calculations:
Cd = 0.605 + 1 / (1000 x 0.5) + 0.08 x 0.5 / 0.75 = 0.66
Q = 0.66 x (2/3) x 1.5 x (2 x 9.812)0.5 x 0.53/2 =
1.034 m3/secQ = 0.66 x (2/3) x (1.5 - 0.1 x 2 x 0.5) x (2 x 9.812)0.5 x 0.53/2 =
0.965 m3/secLast Modified on: 04-Feb-2022
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