At the tip of the opening:
The horizontal component of jet velocity Vx = (2gh)0.5 = dx/dt
And the vertical component Vz = 0
One the jet is left the orifice, it is acted upon by gravitational forces. This makes the vertical component of velocity to equal -gt.
i.e., Vz = -gt = dz/dt
The horizontal and vertical distances covered in time t are, obtained from integrating the above equations.
x = (2gh)0.5 t
and z = -gt2/2
And elimination of t can be done as,
z = -g [x2/(2gh)] / 2
z = - x2/(4h)
Let us take downward direction as positive z. Then
x = 2 (hz)0.5
Last Modified on: 14-Sep-2014
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