###
Euler's Equation of Motion

Home ->
Lecture Notes
->
Fluid Mechanics -> Unit-II

Mass in per unit time = rA*v* =

For steady flow, mass out per unit time =

Rate of momentum in =

Rate of momentum out =

Rate of increase of momentum from AB to CD = = rA*v* d*v* à
1

Force due to p in the direction of motion = pA

Force due to p + dp opposing the direction of motion = (p + dp)(A + dA)

Force due to p_{side} producing a component in the direction of motion = p_{side}dA

Force due to mg producing a component opposing the direction of motion = mgcos(q)

Resultant force in the direction of motion = pA - (p + dp)(A + dA) + p_{side}dA - mgcos(q) à
2

The value of p_{side} will vary from p at AB to p + dp at CD, and can be taken as p + kdp where k is fraction.

Mass of fluid element ABCD = m = rg(A + 1/2 dA) ds

And ds = dz/cos(q); since cos(q) = dz/ds

Substituting in equn.2,

Resultant force in the direction of motion = pA - (p + dp)(A + dA) + p + kdp - rg(A + 1/2 dA) dz

= -Adp - dpdA + kdpdA - rgAdz - 1/2 dAdz

Neglecting products of small quantities,

Resultant force in the direction of motion = -Adp - rgAdz à
3

Applying Newton's second law, (i.e., equating equns.1 & 3)

rA*v* d*v* = -Adp - rgAdz

dividing by rAds,

or, in the limit as ds à
0,

This is known as Euler's equation, giving, in differential form

the relationship between p, *v*, r and elevation z, along a streamline for steady flow.

It can not be integrated until the relationship density and pressure is known.

For incompressible fluid, r is constant; therefore the Euler's equation is integrated to give the following:

which is nothing but the Bernoulli equation.

Table of Contents

HOME

Last Modified on: 14-Sep-2014

Chemical Engineering Learning Resources - msubbu

e-mail: msubbu.in[AT]gmail.com

Web: http://www.msubbu.in