Process Calculations - GATE-CH Questions

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Material Balance with Reaction

GATE-CH-1988-1-i-pc-2mark

1988-1-i-pc

Match the following:

GATE-CH-1993-8-b-pc-2mark

1993-8-b-pc

Methane is completely burnt with air. The maximum possible volume percent of carbon dioxide (on dry basis) in the flue gas is

GATE-CH-1995-2-h-pc-2mark

1995-2-h-pc

Pure \(\ce {O2}\) is mixed with air to produce an enriched air containing 50 volume % of \(\ce {O2}\). The ratio of moles of air to \(\ce {O2}\) used is

GATE-CH-1998-1-8-pc-1mark

1998-1-8-pc

Pure ethanol vapor is fed to a reactor packed with Alumina catalysts at the rate of 100 kmol/h. The reactor product comprise: Ethylene = 95 kmol/h, Water vapor = 97.5 kmol/h and diethyl ether = 2.5 kmol/h.
The reactions occurring can be represented by: \[ \begin {align*} \ce {C2H5OH} &\rightarrow \ce {C2H4} + \ce {H2O} \\
2 \ce {C2H5OH} &\rightarrow \ce {C2H5-O-C2H5} + \ce {H2O} \end {align*}\]
The percent conversion of ethanol in the reactor is:

GATE-CH-1999-1-6-pc-1mark

1999-1-6-pc

Pure \(A\) in gas phase enters a reactor. 50% of this \(A\) is converted to \(B\) through the reaction \(A \rightarrow 3B\). Mole fraction of \(A\) in the exit stream is


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GATE-CH-1988-1-ii-a-pc-1mark

1988-1-ii-a-pc

Carbon is burnt with air. Maximum possible volume percent \(\ce {CO2}\) in the flue gas is 末末- %

GATE-CH-1992-2-b-pc-2mark

1992-2-b-pc

1.2 gatoms of carbon and 1.5 gmol of oxygen are reacted to give 1 gmol of carbon dioxide. (i) The limiting reactant is 末末- . (ii) The percent excess reactant supplied is 末末-

(i)
{#1}

(ii)
{#2}

GATE-CH-1995-6-pc-5mark

1995-6-pc

Methanol is produced by the reaction of \(\ce {CO}\) with \(\ce {H2}\) as \[ \ce {CO} + 2\ce {H2} \rightarrow \ce {CH3OH} \] Only 15% of carbon monoxide entering the reactor is converted to methanol. The methanol formed is condensed and recovered completely. The unreacted \(\ce {CO}\) and \(\ce {H2}\) are recycled back to the reactor. The fresh feed will contain \(\ce {H2}\) and \(\ce {CO}\) in the molar ratio of 2:1. For 3200 kg/h of methanol produced, calculate:
(i) kmol/h of fresh feed
{#1}

(ii) kmol/h of recycle gas
{#2}

GATE-CH-1996-12-pc-5mark

1996-12-pc

Methanol vapor can be converted into formaldehyde by the following reaction scheme: \[ \begin {align*} \ce {CH3OH} + \ce {1/2 O2} &\rightarrow \ce {HCHO} + \ce {H2O} \\
\ce {CH3OH} &\rightarrow \ce {HCHO} + \ce {H2} \end {align*} \]
The fresh feed to the process was 0.5 kmol/h of \(\ce {O2}\) and an excess methanol. All of the \(\ce {O2}\) reacts in the reactor. Formaldehyde and water are removed from the product stream first, after which \(\ce {H2}\) is removed from the recycled methanol. The recycle flow rate of methanol was 1 kmol/h. The ratio of methanol reacting by decomposition to that by oxidation was 3. Draw the flow diagram and then calculate: (i) the per pass conversion of methanol in the reactor, and, (ii) the fresh feed rate of methanol (kmol/h).
(i) ____________
{#1}

(ii) ____________
{#2}

GATE-CH-1997-2-4-pc-2mark

1997-2-4-pc

Pure carbon is completely burnt in oxygen. The flue gas analysis is 70% \(\ce {CO2}\), 20% \(\ce {CO}\) and 10% \(\ce {O2}\). The percent excess oxygen used is


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GATE-CH-1997-2-5-pc-2mark

1997-2-5-pc

The flowsheet is given in figure.

  

If the single-pass conversion (once-through conversion) of \(A\) to \(B\) is 20%, then the rate of recycle \(R\) (mol/h) is

GATE-CH-2001-2-3-pc-2mark

2001-2-3-pc

A butane isomerization process produces 70 kmol/h of pure isobutane. A purge stream removed continuously, contains 85% n-butane and 15% impurity (mole %). The feed stream is n-butane containing 1% impurity (mole %). The flow rate of the purge stream will be:

GATE-CH-2003-38-pc-2mark

2003-38-pc

6 g of carbon is burnt with an amount of air containing 18 g oxygen. The product contains 16.5 g CO2 and 2.8 g CO besides other constituents. What is the degree of conversion on the basis of disappearance of the limiting reactant?

GATE-CH-2005-43-pc-2mark

2005-43-pc

A feed stream (\(S_1\)) at 100 kg/h and containing only \(A\) mixes with recycle stream \(S_5\) before entering the reactor (see the figure below), where the reaction \(A\rightarrow B\) takes place. The operation is at steady state. The stream \(S_3\) leaving the reactor is separated, without either phase or composition change, into two streams \(S_4\) and \(S_5\). If the mass fraction of \(B\) in \(S_4\) is 0.95 and total flow rate of \(S_5\) is 10 kg/h, then the ratio of flow rates of streams \(S_3/S_5)\), and the flow rate of \(A\) in \(S_3\) are, respectively,


GATE-CH-2008-31-pc-2mark

2008-31-pc

Air (79 mole% nitrogen and 21 mole% oxygen) is passed over a catalyst at high temperature. Oxygen completely reacts with nitrogen as shown below \[ \begin{align*}0.5 \text{N}_2\text{(g)} + 0.5 \text{O}_2\text{(g)} &\rightarrow \text{NO}\text{(g)} \\ 0.5 \text{N}_2\text{(g)} + \text{O}_2\text{(g)} &\rightarrow \text{NO}_2\text{(g)}\end{align*} \] The molar ratio of NO to NO2 in the product stream is 2:1. The fractional conversion of nitrogen is


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GATE-CH-2008-34-pc-2mark

2008-34-pc

Carbon black is produced by decomposition of methane: \[ \text{CH}_4\text{(g)} \rightarrow \text{C}\text{(s)} + 2\text{H}_2\text{(g)} \] The single pass conversion of methane is 60%. If fresh feed is pure methane and 25% of the methane exiting the reactor is recycled, then the molar ratio of fresh feed stream to recycle stream is

GATE-CH-2011-31-pc-2mark

2011-31-pc

Ammonia is synthesised at 200 bar and 773 K by the reaction \( \text{N}_2 + 3\text{H}_2 \rightleftharpoons 2\text{NH}_3\). The yield of ammonia is 0.45 mol/mol of fresh feed. Flow sheet for the process (along with available compositions) is shown below.


The single-pass conversion for H2 in the reactor is 20%. The amount of H2 lost in the purge as a PERCENTAGE of H2 in fresh feed is

GATE-CH-1989-1-iii-pc-2mark

1989-1-iii-pc

In a reaction mixture the reactants \(\ce {CO}\) and \(\ce {O2}\) are present in the mole ratio of 1:0.4. Starting with a total of 1.4 moles of the reactants, the products obtained after oxidation of \(\ce {CO}\) to \(\ce {CO2}\) contain: \(\ce {CO2}\) = 0.6 moles, \(\ce {CO}\) = 0.4 moles, \(\ce {O2}\) = 0.1 moles. The degree of completion of the oxidation reaction is 末末- %.

GATE-CH-1989-11-ii-pc-4mark

1989-11-ii-pc

The gases entering a reactor contain \(A\) and \(B\) in the mole ratio of 1:4. The mole ratio of these gases in the exit stream from the reactor is 1:4.25. What volume of the gas in m\(^3\) at STP must enter the reactor to produce 100 kmol of product \(C\) per hour?
The reaction is \(A + 3B \rightarrow 2C\).

GATE-CH-1990-11-ii-pc-6mark

1990-11-ii-pc

For the reaction \(A\rightarrow B\), the process flow diagram is shown in figure. The fresh feed of \(A\) consists of 0.5% of inerts by volume. 60% conversion per pass of \(A\) fed to the reactor is obtained. The concentration of inerts going into the reactor at (1) must be held at 2% by volume. All streams are ideal gases and the process is at steady state. How many moles need to be recycled per mole of total feed to the reactor at (1).



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GATE-CH-1991-12-ii-pc-6mark

1991-12-ii-pc

Limestone mixed with coke is being burnt in a kiln. An average analysis of limestone is \(\ce {CaCO3}\): 84.5%, \(\ce {MgCO3}\): 11.5% and the rest inerts. The coke contains 76% carbon, 21% ash and 3% moisture. The calcination of \(\ce {CaCO3}\) is only 95% complete and that of \(\ce {MgCO3}\) 90%. The carbon in the coke is completely burnt to \(\ce {CO2}\). The kiln is fed with 1 kg of coke per 5 kg limestone. Calculate weight percent \(\ce {CaO}\) in the product leaving the kiln.

GATE-CH-1992-12-a-pc-6mark

1992-12-a-pc

The analysis of the gas entering the secondary converter in a contact sulphuric acid plant is 4% \(\ce {SO2}\), 13% \(\ce {O2}\) and 83% \(\ce {N2}\) (volume %). In the converter \(\ce {SO2}\) is oxidized to \(\ce {SO3}\). The gases leaving the converter contain 0.45% \(\ce {SO2}\) on an \(\ce {SO3}\) - free basis (volume %). Calculate the percent conversion of \(\ce {SO2}\).

GATE-CH-2014-41-pc-2mark

2014-41-pc

Two elemental gases (\(A\) and \(B\)) are reacting to form a liquid (\(C\)) in a steady state process as per the reaction \(A + B \rightarrow C\). The single-pass conversion of the reaction is only 20% and hence recycle is used. The product is separated completely in pure form. The fresh feed has 49 mol% of \(A\) and \(B\) each along with 2 mol% impurities. The maximum allowable impurities in the recycle stream is 20 mol%. The amount of purge stream (in moles) per 100 moles of the fresh feed is ________.

GATE-CH-1988-11-i-pc-6mark

1988-11-i-pc

Exit gases from an ethylene oxide reactor had the following analysis (mol% on dry basis): ethylene 2.3, ethylene oxide 0.9, nitrogen 79.0, oxygen 12.3 and carbon dioxide 5.5. Calculate: 

(a) percent selectivity
{#1}

(b) percent overall conversion
{#2}

(c) moles of air per mole of ethylene in the feed mixture.
{#3}

GATE-CH-1993-18-pc-5mark

1993-18-pc

Iron pyrites (\(\ce {FeS2}\)) is burned with air in 100% excess of that required to oxidise all iron to \(\ce {Fe2O3}\) and all sulphur to sulphur dioxide. Calculate the composition (in mol%) of exit gases, if 80% of sulphur is oxidised to sulphur trioxide and the rest to sulphur dioxide. All iron is oxidised to \(\ce {Fe2O3}\).
(i) \(\ce {SO2}\)
{#1}

(ii) \(\ce {SO3}\)
{#2}

(iii) \(\ce {O2}\)
{#3}

(iv) \(\ce {N2}\)
{#4}


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GATE-CH-2007-78-79-pc-4mark

2007-78-79-pc

A simplified flowsheet is shown in the figure for production of ethanol from ethylene. The conversion of ethylene in the reactor is 30% and the scrubber following the reactor completely separates ethylene (as top stream) and ethanol and water as bottoms. The last (distillation) column gives an ethanol-water azeotrope (90 mol% ethanol) as the final product and water as waste. The recycle to purge ratio is 34.


The reaction is : C2H4(g) + H2O(g) \(\rightarrow\) C2H5OH(g)

(i) For an azeotrope product rate of 500 mol/h, the recycle gas flowrate in mol/h is

{#1}

(ii) For the same process, if fresh H2O feed to the reactor is 600 mol/h and wash water for scrubbing is 20% of the condensables coming out of the reactor, the water flowrate in mol/h from the distillation column as bottoms is

{#2}

GATE-CH-1998-3-pc-5mark

1998-3-pc

Ethylene oxide is produced by the oxidation of ethylene over a catalyst. Safety considerations dictate that the gaseous mixture entering the reactor should contain 10 mol air per mol ethylene. The conversion per pass is 22%. The ethylene oxide formed is completely condensed out and the remaining gases recycled. Make up oxygen is added to maintain the request oxygen levels. For a plant producing 440 kg/h of ethylene oxide,

  1. Calculate the quantity of pure makeup oxygen to be supplied, in kg/h, in steady state operation.

  2. Draw a neat block diagram showing the major units, flows and compositions, and indicate the envelope / boundary around which the requisite mass balance(s) is / are made.

The relevant reaction is represented by \[2\ce{C2H4(g)} + \ce{O2(g)} \rightarrow 2\ce{C2H4O(g)}\] [Atomic masses as: C = 12, O = 16, H = 1].

GATE-CH-1999-6-pc-5mark

1999-6-pc

It is proposed to produce acetaldehyde by oxidation of ethanol in gas phase \[ \ce {C2H5OH + 1/2 O2(g)} \rightarrow \ce {CH3CHO(g)} + \ce {H2O(g)} \] The ratio of air to ethanol in fresh feed (before it is mixed with recycle stream) is 10 to 1. The conversion of ethanol on a single pass through reactor is 25%. The unreacted ethanol is completely separated from the reaction products and recycled. What is the ratio of recycle stream to the fresh feed stream? What is the composition of the outlet stream from the reactor in mass fraction and mole fraction?

GATE-CH-2001-5-pc-5mark

2001-5-pc

The process schematic of a propane dehydrogenation plant is shown below. It is desired to set up a simplified version of the material balance for this plant. Assume that the only reaction is the dehydrogenation of propane to propylene; there are no side reactions. The yield of propylene per pass is 30% (i.e., 30% of propane entering the reactor is converted to propylene). Assume that the amount of carbon formed on the catalyst is negligible. The product flow rate (stream \(S_5\)) is 50 kmol/h. Calculate the flow rates of all the other streams. Notice that all streams except stream \(S_3\) are pure.




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Last Modified on: 04-May-2024

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