Mass Transfer - GATE-CH Questions
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Extraction
GATE-CH-2006-14-mt-1mark
An ideal single stage extraction process is used to treat 100 mol/s of an organic feed solution. The solute concentration in this solution is to be reduced from 0.5 mol% to 0.1 mol%. A pure solvent is used. To reduce the solvent requirement by half
for the same separation,
GATE-CH-2008-8-mt-1mark
For a system containing species , and , composition at point on the ternary plot is

GATE-CH-2017-14-mt-1mark
Which of the following conditions are valid at the plait point?
- [P)] Density difference between the extract and raffinate phases is zero
- [Q)] Interfacial tension between the extract and raffinate phases is zero
- [R)] Composition difference between the extract and raffinate phases is zero
GATE-CH-1987-15-ii-mt-2mark
Acetone from 1 kg of an aqueous solution containing 20% acetone (by weight) is to be extracted using 1 kg of an organic solvent trichloroethane. Trichloroethane and water are immiscible. The distribution coefficient, Estimate the amounts of acetone (kg) in (i) extract phase and (ii) aqueous phase at equilibrium.
(i) ____________
{#1}
(ii) ____________
{#2}
GATE-CH-2006-76-77-mt-4mark
Solvent is used to extract solute selectively from, 100 kg/h feed mixture in a steady state continuous process shown below. The solubility of in the raffinate and the solubility of in the extract are negligible. The extract
is distilled to recover in the bottom product. The overhead product is recycled to the extractor. The loss of solvent in the bottoms is compensated by make up solvent . The total flow rate of the solvent stream going to the extractor
is 50 kg/h. The mass fractions (�s) of some selected streams are indicated in the figure below.

(i) Distillation bottoms flow rate W and solvent dosing rate in kg/h are
{#1}
(ii) Feed rate to the distillation column and overhead product rate in kg/h are
{#2}
[Index]
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GATE-CH-2012-48-49-mt-4mark
A counter-current extraction column is designed to remove 99% of solute from a solution of solvent and solute using pure solvent . The initial concentration of solute in the solution of is 20 wt%, and the total flow of solution
is 1000 kg/h. If the equilibrium relationship is , where = mass of /mass of , and = mass of /mass of .
(i) The minimum flow rate of solvent required (in kg/h) is
{#1}
(ii) If the flow rate of is 2400 kg/h, then the theoretical number of stages in the column, using Kremser�s equation (adjusted to the next integer) is
{#2}
GATE-CH-2001-2-14-mt-2mark
In a single stage extraction process, 10 kg of pure solvent (containing no solute ) is mixed with 30 kg of feed containing at a mass fraction = 0.2. The mixture splits into an extract phase and a raffinate phase ,
containing at and , respectively. The total mass of the extract phase is (in kg)
GATE-CH-2004-66-mt-2mark
In liquid-liquid extraction 10 kg of a solution containing 2 kg of solute and 8 kg of solvent is brought into contact with 10 kg of solvent . Solvents and are completely immiscible in each other whereas solute is soluble
in both the solvents. The extraction process attains equilibrium. The equilibrium relationship between the two phases is where is kg of /kg of and is kg of /kg of . Choose the correct answer
GATE-CH-2005-42-mt-2mark
In the triangular diagram represented below for a batch separation process, a stream is mixed with a solvent to produce products and . Substance is the carrier liquid and is the solute to be extracted. The amounts of
and are 1 kg and 1.20 kg respectively. The length is 3.1 and length is 8.5 units on the figure. The ratio is estimated to be

GATE-CH-2007-50-mt-2mark
It is desired to reduce the concentration of pyridine in 500 kg of aqueous solution from 20 weight percent to 5 weight percent in a single batch extraction using chloro-benzene as solvent. Equilibrium compositions (end points of the tie line) in terms
of weight percent of pyridine-water-chlorobenzene are (5, 95, 0) and (11, 0, 89). The amount of pure solvent required in kg for the operation is
[Index]
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GATE-CH-2008-54-mt-2mark
A feed () containing a solute is contacted with a solvent () in an ideal stage as shown in the diagram below. Only the solute transfers into the solvent. The flow rates of all the streams are shown on a solute free basis and indicated by the
subscript . The compositions of the streams are expressed on a mole ratio basis. The extract leaving the contactor is divided into two equal parts, one part collected as the product () and the other stream is recycled to join the solvent.
The equilibrium relationship is The product flow rate () and composition () are

GATE-CH-2016-44-mt-2mark
Solute is extracted in a batch process from its homogeneous solution of and , using solvent . The combined composition of the feed and the extracting solvent is shown in the figure below as point , along with the tie line passing
through it. The ends of the tie line are on the equilibrium curve.

What is the selectivity for ?
GATE-CH-1996-22-mt-5mark
990 kg/h of an aqueous solution has a solute at a concentration of 0.1 kg solute/ kg water. It is treated with 600 kg/h of a pure immiscible organic solvent in a 2-stage mixer-settler system. If the organic and aqueous streams leaving each stage are in
equilibrium such that calculate the kg solute extracted per kg
solvent if countercurrent operation is employed.
GATE-CH-2000-10-mt-5mark
A continuous-contact extraction column is used to extract a solute from an aqueous stream () using an organic solvent (). The distribution coefficient ()
is 1.0, where and are the mass fractions of solute in raffinate and extract phases, respectively. The height of transfer unit based on the extract phase is 1.0 m. The rest
of the data are given in the figure. Assuming that the phase flow rates are constant, find the height of the tower (in m).

GATE-CH-1995-3-d-mt-2mark
Match the following:
[Index]
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GATE-CH-1991-16-ii-mt-8mark
An aqueous solution containing 1.5 kmol of solute/m is fed at 36 mL/s to the top of the packed column of height 1.6 m and cross sectional area of 0.0045 m and it leaves at the bottom with 1.4 kmol/m. An organic solvent, , containing
0.008 kmol of solute/m flows counter to the aqueous phase at 9 mL/s. The equilibrium relationship is where is the concentration of solute in solvent rich phase; and is that of in aqueous phase.
Determine:
(a) the log mean concentration difference for the transfer (in mole fraction).
{#1}
(b) the overall volumetric transfer coefficient (in s), based on the organic phase. ____________
{#2}
(c) the height of transfer unit (in m).
{#3}
GATE-CH-1993-23-mt-5mark
A mineral containing 20% elemental sulfur is to be leached with hot gas oil in which sulfur is soluble to the extent of 10 parts in 100 parts of oil by weight. The oil is recycled over the batch of ground mineral till no further dissolution of sulfur
takes place. On drainage, the solid minerals retain the solution to the extent of one-tenth the weight of undissolved solid (sulfur and gauge). No preferential adsorption takes place. Calculate the equilibrium compositions and quantities of the solid
and liquid phases if 50 kg of oil is used for leaching 100 kg of fresh mineral.
GATE-CH-2002-14-mt-5mark
It is desired to extract acetone from a feed containing acetone and water, using chloroform as the solvent, in two cross current extraction stages as shown below:

Assume that water and chloroform are immiscible. The following data are given for the process:
-
The feed is an equimolar mixture of acetone and water.
-
The quantities of chloroform used in the two stages are equal.
-
60 mole % of the acetone in the feed is extracted in stage I.
-
The extract and raffinate phases exiting from each stage are in equilibrium. The equilibrium relation for the distribution of the acetone is given by
-
Indicate (with the help of the above diagram) the components in each stream.
-
Determine the quantity of chloroform used in each stage per mole of feed.
-
Determine the mole fraction of acetone in final product stream.
[Index]
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Last Modified on: 03-May-2024
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