0300-2-fm

Indicate what will be the manometric reading if the venturi meter is replaced by an orifice meter of the same size:

- less than that for venturi meter
- same as that for venturi meter
- higher than that for venturi meter

1994-2-i-fm

For an orifice meter, the pressure recovery is ––––- than that for a venturi meter.

- less
- more

1995-2-m-fm

A Pitot tube indicates 5 cm of water (manometer) when it is being used for measuring velocity of air. The velocity of air in m/s is

- 5
- 14.1
- 56.22
- 28.2

1996-2-4-fm

A rotameter, through which air at room temperature and atmospheric pressure is flowing, gives a certain reading for a flow rate of 100 cc/s. If helium (Molecular weight 4) is used and the rotameter shows the same reading, the flow rate is

- 26 cc/s
- 42 cc/s
- 269 cc/s
- 325 cc/s

2001-1-7-fm

The operation of a rotameter is based on

- variable flow area
- rotation of a turbine
- pressure drop across a nozzle
- pressure at a stagnation point

2011-23-fm

In an orifice meter, if the pressure drop across the orifice is overestimated by 5%, then the PERCENTAGE error in the measured flow rate is

- \(+2.47\)
- \(+5\)
- \(-2.47\)
- \(-5\)

2012-11-fm

The local velocity of a fluid along a streamline can be measured by

- Pitot tube
- Venturi meter
- Rotameter
- Orifice meter

IN-2013-18-fm

The differential pressure transmitter of a flow meter using a venturi tube reads \(2.5\times 10^5\) Pa for a flow rate of 0.5 m^{3}/s. The approximate flow rate in m^{3}/s for a differential pressure \(0.9\times 10^5\) Pa is

- 0.30
- 0.18
- 0.83
- 0.60

1987-12-iv-fm

A liquid of specific gravity 1.25 is draining from the bottom of a large open tank through a 50 mm ID pipe. The drain pipe ends at a position 5 m below the surface of the liquid in the tank. Calculate the velocity of flow (in m/s) at the point of discharge
from the pipe. Explain the significance of the result.

____________

2014-50-fm

In a steady and incompressible flow of a fluid (density = 1.25 kg/m^{3}), the difference between stagnation and static pressures at the same location in the flow is 30 mm of mercury (density = 13600 kg/m^{3}). Considering gravitational
acceleration as 10 m/s^{2}, the fluid speed (in m/s) is ____________

1999-9-fm

Flow rate of water flowing through a pipe is being measured by using an orifice meter as shown in the figure.

- What is the direction of flow in the pipe? {#1}
- Derive an expression for velocity through the orifice. Determine the flow rate (ltr/s) for an orifice coefficient of 0.8 {#2}

2003-75-fm

The pressure differential across a vertical venturi meter (shown in figure) is measured with the help of a mercury manometer to estimate flow rate of water flowing through it. The expression for the velocity of water at the throat is

- \(\displaystyle \frac {v_2^2-v_1^2}{2g} = \frac {h\rho _m}{\rho _f}\)
- \(\displaystyle \frac {v_2^2-v_1^2}{2g} = \frac {h(\rho _m-\rho _w)}{\rho _f}\)
- \(\displaystyle \frac {v_2^2-v_1^2}{2g} = H + \frac {h(\rho _m-\rho _w)}{\rho _f}\)
- \(\displaystyle \frac {v_2^2}{2g} = \frac {h(\rho _m-\rho _w)}{\rho _f}\)

2007-39-fm

The pressure differential across a venturi meter, inclined at 45^{o} to the vertical (as shown in the figure) is measured with the help of a manometer to estimate the flowrate of a fluid flowing through it. If the density of the flowing fluid
is \(\rho \) and the density of the manometer fluid is \(\rho _m\), the velocity of the fluid at the throat can be obtained from the expression

- \(\displaystyle \frac {v_2^2-v_1^2}{2g} = \frac {h(\rho _m-\rho )}{\rho } + H\sin 45^{\circ }\)
- \(\displaystyle \frac {v_2^2-v_1^2}{2g} = \frac {h\rho _m}{\rho } + H\sin 45^{\circ }\)
- \(\displaystyle \frac {v_2^2-v_1^2}{2g} = \frac {h\rho _m}{\rho }\)
- \(\displaystyle \frac {v_2^2-v_1^2}{2g} = \frac {h(\rho _m-\rho )}{\rho }\)

CE-2018-S2-34-fm

In a 5 m wide rectangular channel, the velocity \(u\) distribution in the vertical direction \(y\) is given by \(u=1.25y^{1/6}\). The distance \(y\) is measured from the channel bed. If the flow depth is 2 m, the discharge per unit width of the channel is

- 2.40 m
^{3}/s/m - 2.80 m
^{3}/s/m - 3.27 m
^{3}/s/m - 12.02 m
^{3}/s/m

1987-12-ii-fm

Air is flowing in a 50 mm ID tube. There is a venturi meter in the line, and the manometric fluid is water. Calculate the volumetric flow rate of air (in m\(^3\)/s) for the following conditions:

Manometric reading = 100 mm water

Density of water = 1000 kg/m\(^3\)

Density of air = 1.185 kg/m\(^3\)

Coefficient of discharge = 0.98

Diameter of venturi throat = 25 mm

Pressure of air = 1 atm.

____________

1991-13-i-fm

What diameter of orifice (in mm) would give a pressure difference of 41 cm water column for the flow of liquid styrene of specific gravity 0.9 at 0.055 m\(^3\)/s in a 250 mm diameter pipe? Assume \(C_d = 0.62\)

____________

1993-19-a-fm

Water flows through a 30 mm i.d. pipe at atmospheric pressure. The velocity of water at the center of the pipe is measured by a Pitot tube as shown in Figure. The pressure difference between the impact tube and the static tube is 20 cm of Carbon tetra
chloride (density = 1600 kg/m\(^3\)). Calculate the volumetric flow rate through the pipe in cubic meter per hour. Viscosity of water is 1 cP.

____________

Last Modified on: 02-May-2024

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