Process Control - GATE-CH Questions

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Frequency Response

GATE-CH-1995-1-q-ctrl-1mark

1995-1-q-ctrl

Bode diagrams are generated from output response of the system subjected to which of the following input

GATE-CH-1995-1-t-ctrl-1mark

1995-1-t-ctrl

According to Bode stability criterion, a system is unstable if the open loop frequency response exhibits an amplitude ratio exceeding unity at frequency for which phase lag is

GATE-CH-1998-1-24-ctrl-1mark

1998-1-24-ctrl

A first order system with a time constant of 1 min is subjected to frequency response analysis. At an input frequency of 1 radian/min, the phase shift is

GATE-CH-1999-1-27-ctrl-1mark

1999-1-27-ctrl

A sinusoidal variation in the input passing through a linear first-order system

GATE-CH-2000-1-27-ctrl-1mark

2000-1-27-ctrl

Select the correct statement from the following:


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GATE-CH-2000-1-28-ctrl-1mark

2000-1-28-ctrl

For a feedback control system to be stable, the

GATE-CH-2002-1-15-ctrl-1mark

2002-1-15-ctrl

A first order system with unity gain and time constant \(\tau\) is subjected to a sinusoidal input of frequency \(\omega=1/\tau\). The amplitude ratio for this system is

GATE-CH-2002-2-16-ctrl-2mark

2002-2-16-ctrl

The frequency response of a first order system, has a phase shift with lower and upper bounds given by

GATE-CH-2010-24-ctrl-1mark

2010-24-ctrl

The transfer function, \(G(s)\), whose asymptotic Bode diagram is shown below, is

GATE-CH-2012-25-ctrl-1mark

2012-25-ctrl

The Bode stability criterion is applicable when


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GATE-CH-1992-19-b-ctrl-6mark

1992-19-b-ctrl


For the loop above, determine: 

(i) The maximum gain for stable operation.
{#1}

(ii) The corresponding frequency of oscillation (rad/min).
{#2}

GATE-CH-1997-26-ctrl-2mark

1997-26-ctrl

The open loop transfer function for a process is \(\dfrac {1}{4(3s+1)^4}\), where the time constant is in minutes.
Determine: 

(i) the crossover frequency (rad/min)
{#1}

(ii) the ultimate gain.
{#2}

GATE-CH-2000-14-ctrl-5mark

2000-14-ctrl

A feedback control loop with a proportional controller has an open loop transfer function \(G_L(s) = \dfrac {K_c}{s(5s+1)^2}\) where time is in minutes.

(i) The crossover frequency in radians/min = _________

{#1}

(ii)The ultimate controller gain = _________

{#2}

GATE-CH-2006-84-85-ctrl-4mark

2006-84-85-ctrl

For the system shown below, \(G_1(s) = \dfrac {1}{\tau _1s+1}\), \(G_2(s)=\dfrac {1}{\tau _2s+1}\) and \(\tau _2=2\tau _1\).

 
When the system is excited by the sinusoidal input \(X(t) = \sin \omega t\), the intermediate response \(Y\) is given by \( Y = A\sin (\omega t+\phi )\)

(i) If the response \(Y\) lags behind the input \(X\) by 45\(^\circ \) and \(\tau _1=1\), then the input frequency \(\omega \) is
{#1}

(ii) For the same input, the amplitude of the output \(Z\) will be
{#2}

GATE-CH-1998-2-21-ctrl-2mark

1998-2-21-ctrl

The frequency response of a dynamic element shows a constant magnitude ratio at all frequencies. The element exhibits a negative phase shift at all frequencies. The absolute value of the phase shift increases linearly with frequency. The element has the transfer function


[Index]



GATE-CH-2000-2-23-ctrl-2mark

2000-2-23-ctrl

The time constant of a unity gain, first order plus time delay process is 5 min. If the phase lag at a frequency of 0.2 rad/min is 60o, then the dead time (in minutes) is

GATE-CH-2001-2-18-ctrl-2mark

2001-2-18-ctrl

An ideal PID controller has the transfer function \(\left[1+\dfrac{1}{0.5s} + 0.2s\right]\). The frequency at which the magnitude ratio of the controller is 1, is

GATE-CH-2003-77-ctrl-2mark

2003-77-ctrl

Find the ultimate gain and frequency for a proportional controller in the case of a process having the following transfer function

\[ G_p(s) = \frac{1}{(4s+1)(2s+1)(s+1)} \]

GATE-CH-2004-80-ctrl-2mark

2004-80-ctrl

Consider a system with open-loop transfer function

\[ G(s) = \frac{1}{(s+1)(2s+1)(5s+1)} \]

Match the range of \(\omega\) (frequency) in Group I with the slope of the asymptote of the \(\log \text{AR}\) (amplitude ratio) versus \(\log \omega\) plot in Group II.


Group I    Group II

(P) \(0 < \omega < 0.2\)  

(1) \(\quad -5\) 

(Q) \(\omega > 1\)

(2) \(\quad -3\)

(3) \(\quad -2\)

(4) \(\quad -1\)

 

(5) \(\quad \)zero

GATE-CH-2005-50-ctrl-2mak

2005-50-ctrl

The value of ultimate period of oscillation \(P_u\) is 3 minutes, and that of the ultimate controller gain \(K_{cu}\) is 2. Select the correct set of tuning parameters (controller gain \(K_c\), derivative time constant \(\tau_D\) in minutes, and the integral time constant \(\tau_I\) in minutes) for a PID controller using Ziegler-Nichols controller settings.


[Index]



GATE-CH-2006-58-ctrl-2mark

2006-58-ctrl

A process is perturbed by a sinusoidal input, \(u_t = A \sin \omega t\). The resulting process output is \(Y(s) = \dfrac{K A\omega}{(\tau s+1)(s^2+\omega^2)}\). If \(y(0) = 0\), the differential equation representing the process is

GATE-EE-2013-A-15-ctrl-1mark

EE-2013-A-15-ctrl

The Bode plot of a transfer function \(G(s)\) is shown in the figure below.


The gain \((20\log |G(s)|)\) is 32 dB and -8 dB at 1 rad/s and 10 rad/s respectively. The phase is negative for all \(\omega\). Then \(G(s)\) is

GATE-IN-2014-23-ctrl-1mark

IN-2014-23-ctrl

A plant has an open-loop transfer function, \[ G_p(s) = \frac{20}{(s+0.1)(s+2)(s+100)} \] The approximate model obtained by retaining only one of the above poles, which is closest to the frequency response of the original transfer function at low frequency is

GATE-CH-2017-51-ctrl-2mark

2017-51-ctrl

The open loop transfer function of a process with a proportional controller (gain \(K_c\)) is \[ G_{OL} = K_c\frac{e^{-2s}}{s} \] Based on Bode criterion for closed-loop stability, the ultimate gain of the controller, rounded to 2 decimal places, is ______

GATE-CH-2018-44-ctrl-2mark

2018-44-ctrl

Consider the following transfer function: \[ G(s) = \frac{3}{(5s+1)^2} \] where, the natural period of oscillation is in min. The amplitude ratio at a frequency of 0.5 rad/min is ________ (rounded off to second decimal place).


[Index]



GATE-CH-2019-49-ctrl-2mark

2019-49-ctrl

For the closed loop system shown in figure, the phase margin (in degrees) is ___________


GATE-IN-2014-46-ctrl-2mark

IN-2014-46-ctrl

The transfer function of a system is given by \(\displaystyle G(s) = \frac{e^{-s/500}}{s+500}\). The input to the system is \(x(t)=\sin 100\pi t\). In periodic steady state the output of the system is found to be \(y(t)=A\sin(100\pi t - \phi)\). The phase angle (\(\phi\)) in degree is _______

GATE-CH-1999-2-18-ctrl-2mark

1999-2-18-ctrl

Each item given in the left-hand column is closely associated with a specific characteristic listed in the right-hand column. Match each of the items with the corresponding characteristic.


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Last Modified on: 02-May-2024

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