A tank having a volume of 0.1 m3 contains air at 14 MPa and 50oC. It is connected through a valve to a larger tank having a volume of 15 m3, which is completely evacuated. The entire assembly is completely insulated. The valve is opened and the gas allowed to come to equilibrium in both tanks. Calculate the final pressure.
For this process, Q = 0 and W = 0. Therefore, DU = 0.
DU = mCvDT = 0.
Therefore, DT = 0.
For an ideal gas, PV = nRT
Since T is constant, P1V1 = P2V2
14 x 0.1 = P2 x (0.1 + 15)
i.e., final pressure
P2 = 92.715 KPa.
Last Modified on: 11-Sep-2014
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