firstname.lastname@example.org | 7338856161
Liquid water at 100oC and 1 bar has an internal energy (on an arbitrary scale) of 419 kJ/kg and a specific volume of 1.044 cm3/g.
(a) What is its enthalpy?
(b) The water is brought to the vapor state at 200oC and 800 kPa, where its enthalpy is 2838.6 kJ/kg and its specific volume is 260.79 cm3/g. Calculate DU and DH for the process.
(a) Enthalpy = U + PV
= 419 + 100 kPa x 1.044 x 10-3 m3/kg = 419 + 0.1044 = 419.1044 kJ/kg
(b)Internal energy of water vapor at 200oC and 800 kPa = H - PV
= 2838.6 - PV = 2838.6 - 800 x 260.79 x 10-3 = 2838.6 - 208.632 = 2629.968 kJ/kg
DU = 2629.968 - 419 = 2211.968
DH = 2838.6 - 419.1044 = 2419.4956 kJ/kg
Contains the list of courses being taught for the B.Tech Chemical Engineering Students of SSN College of Engineering as per Anna University Chennai syllabus.
Contains the list of courses taught for the B.Tech Chemical Engineering Students of SVCE for the Madras University & Anna University Syllabus..
Contains training Programmes on MATLAB and Simulink for Chemical Engineering Applications and etc.
Contains how this was Established and Evolved